((2/6)x^2)-6=-4/5x

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Solution for ((2/6)x^2)-6=-4/5x equation:



((2/6)x^2)-6=-4/5x
We move all terms to the left:
((2/6)x^2)-6-(-4/5x)=0
Domain of the equation: 6)x^2)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 5x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
((+2/6)x^2)-(-4/5x)-6=0
We get rid of parentheses
((+2/6)x^2)+4/5x-6=0
We calculate fractions
(((+2*5x)/6x^2)*5x)+24x/6x^2)*5x)-6=0
We calculate terms in parentheses: +(((+2*5x)/6x^2)*5x), so:
((+2*5x)/6x^2)*5x
We multiply all the terms by the denominator
((+2*5x)
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
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(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
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(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
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(+2*5x
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(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
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(+2*5x
We calculate terms in parentheses: +((+2*5x), so:
(+2*5x
Back to the equation:
+(((+2*5x))
We multiply all the terms by the denominator
(((+2*5x))+24x=0

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